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(0.7)^(2)+2.8(5.5)=

$(0.7)^{2}+2.8(5.5)=$

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Powers with decimal bases

Full solution

Q.

(0.7)^{2}+2.8(5.5)=

Calculate Square of $0$ . $7$ : Calculate the square of $0.7$ . To find $(0.7)^{2}$ , we multiply $0.7$ by itself. $0.7 \times 0.7 = 0.49$
Multiply $2.8$ by $5.5$ : Multiply $2.8$ by $5.5$ . $\newline$ To find the product of $2.8$ and $5.5$ , we perform the multiplication. $\newline$ $2.8 \times 5.5 = 15.4$
Add Results: Add the results from Step $1$ and Step $2$ . $\newline$ Now we add $0.49$ (the square of $0.7$ ) to $15.4$ (the product of $2.8$ and $5.5$ ). $\newline$ $0.49 + 15.4 = 15.89$

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