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Divide by using long division.
(10x^(2)+9x-1)÷(2x-1)

Divide by using long division.\newline(10x2+9x1)÷(2x1)\left(10 x^{2}+9 x-1\right) \div(2 x-1)

Full solution

Q. Divide by using long division.\newline(10x2+9x1)÷(2x1)\left(10 x^{2}+9 x-1\right) \div(2 x-1)
  1. Set up division: Set up the long division.\newlineWe will divide the polynomial 10x2+9x110x^2 + 9x - 1 by the binomial 2x12x - 1 using long division.
  2. Find quotient: Determine how many times the leading term of the divisor 2x2x goes into the leading term of the dividend 10x210x^2. rac{10x^2}{2x} is rac{5x}{1}. Write rac{5x}{1} above the long division bar.
  3. Multiply quotient and divisor: Multiply the entire divisor (2x1)(2x - 1) by the quotient found in Step 22 (5x)(5x).5x×(2x1)=10x25x5x \times (2x - 1) = 10x^2 - 5x. Write this result under the dividend.
  4. Subtract result: Subtract the result of Step 33 from the dividend.\newline(10x2+9x1)(10x25x)=14x1(10x^2 + 9x - 1) - (10x^2 - 5x) = 14x - 1. Bring down the next term if necessary.
  5. Determine new quotient: Determine how many times the leading term of the divisor 2x2x goes into the new term 14x14x. rac{14x}{2x} = 7. Write 77 above the long division bar, next to 5x5x.
  6. Multiply new quotient: Multiply the entire divisor (2x1)(2x - 1) by the new quotient found in Step 55 (7)(7).7×(2x1)=14x77 \times (2x - 1) = 14x - 7. Write this result under the 14x114x - 1.
  7. Subtract result: Subtract the result of Step 66 from the new term (14x1)(14x - 1).(14x1)(14x7)=6(14x - 1) - (14x - 7) = 6. This is the remainder.
  8. Write final answer: Write the final answer.\newlineThe quotient is 5x+75x + 7 with a remainder of 66. The final answer is written as 5x+7+62x15x + 7 + \frac{6}{2x - 1}.

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