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Math Problems
Precalculus
Velocity as a rate of change
E
=
43.66
ω
+
208.40
h
E=43.66 \omega+208.40 h
E
=
43.66
ω
+
208.40
h
\newline
The total energy,
E
E
E
, in joules of a metal cylinder with an angular velocity of
ω
\omega
ω
radians per second and a height of
h
h
h
meters above the ground is given by the equation. The height and angular velocity are independent. Which of the following expressions is the energy due to the angular velocity?
\newline
Choose
1
1
1
answer:
\newline
(A)
ω
\omega
ω
\newline
(B)
43
43
43
.
66
66
66
\newline
(C)
43.66
ω
43.66 \omega
43.66
ω
\newline
(D)
43.66
ω
+
208.40
43.66 \omega+208.40
43.66
ω
+
208.40
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Q
=
A
−
I
L
Q=\frac{A-I}{L}
Q
=
L
A
−
I
\newline
The formula gives the quick assets ratio
Q
Q
Q
in terms of a company's current assets,
A
A
A
; inventories,
I
I
I
; and current liabilities,
L
L
L
. Which of the following equations correctly gives the inventories in terms of the quick assets ratio, the current assets, and the current liabilities?
\newline
Choose
1
1
1
answer:
\newline
(A)
I
=
Q
L
−
A
I=QL-A
I
=
Q
L
−
A
\newline
(B)
I
=
A
−
Q
L
I=A-QL
I
=
A
−
Q
L
\newline
(C)
I
=
L
(
Q
−
A
)
I=L(Q-A)
I
=
L
(
Q
−
A
)
\newline
(D)
I
=
L
(
A
−
Q
)
I=L(A-Q)
I
=
L
(
A
−
Q
)
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