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Math Problems
Grade 7
Find missing angles in quadrilaterals II
Interior Angle Sum: Concave Polygons?
\newline
What is the sum of the interior angles of a PENTAGON?
\newline
Use a protractor to measure the five interior angles in concave pentagon. Calculate the su
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Seventh grade y.
5
5
5
Find measures of complementary, supplementary, vertical, and adjacent angles CST
\newline
What is the value of
j
j
j
?
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Seventh grade Y.
5
5
5
Find measures of complementary, supplementary, vertical, and adjacent angles CST
\newline
What is the value of
j
j
j
?
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The ratio of the measure of two supplementary angles is
14
14
14
:
4
4
4
. Find the measure of each angle.
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if the
6
t
h
6^{th}
6
t
h
and
7
t
h
7^{th}
7
t
h
term of a geometric sequence are
5
5
5
and
−
10
-10
−
10
respectively, what is the
1
0
t
h
10^{th}
1
0
t
h
term
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PREVIOUS ANSWER:
\newline
15
5
∘
155^{\circ}
15
5
∘
\newline
ANGLES OF POLYGONS
\newline
Scavenger Hunt
\newline
The sum of the measures of seven out of ten angles in a decagon is
108
6
∘
1086^{\circ}
108
6
∘
. If the three remaining angles are equal in measure, what is the measure of each angle?
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x
=
x=\qquad
x
=
\newline
y
=
y=\qquad
y
=
\newline
z
=
z=\qquad
z
=
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The equations
x
+
y
=
3
x+y=3
x
+
y
=
3
and
−
5
x
−
5
y
=
−
15
-5 x-5 y=-15
−
5
x
−
5
y
=
−
15
are graphed in the
x
y
x y
x
y
plane. Which of the following must be true of the graphs of the two equations?
\newline
Choose
1
1
1
answer:
\newline
(A) The slope of the graph of
x
+
y
=
3
x+y=3
x
+
y
=
3
is
1
1
1
and the slope of the graph of
−
5
x
−
5
y
=
−
15
-5 x-5 y=-15
−
5
x
−
5
y
=
−
15
is
−
1
-1
−
1
.
\newline
B) The graphs of the two equations are perpendicular lines.
\newline
(C) The
y
y
y
-intercept of the graph of
−
5
x
−
5
y
=
−
15
-5 x-5 y=-15
−
5
x
−
5
y
=
−
15
is
−
15
-15
−
15
.
\newline
(D) The graphs of the two equations are the same line.
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Regular and Irregular Triangular Prisms
\newline
Regular Prism
\newline
Irregular Prism
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This means you should not round values or cut oft decimal places Find the intersection of the lines represented by
\newline
y
=
3
x
−
7
y=3x-7
y
=
3
x
−
7
\newline
and
\newline
y
=
−
4
x
+
7
y=-4x+7
y
=
−
4
x
+
7
.
\newline
x
=
x=
x
=
Number
\newline
y
=
y=
y
=
Number
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