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Math Problems
Grade 6
Inequalities with decimal multiplication
Solve for
f
f
f
:
\newline
f
÷
−
2
3
=
−
1
3
f
=
□
\begin{array}{l} f \div-\frac{2}{3}=-\frac{1}{3} \\ f=\square \end{array}
f
÷
−
3
2
=
−
3
1
f
=
□
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Solve for
f
f
f
:
\newline
f
5
=
−
8
f
=
□
\begin{array}{l} \frac{f}{5}=-8 \\ f=\square \end{array}
5
f
=
−
8
f
=
□
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Solve for
f
f
f
:
\newline
2
f
=
−
12
f
=
□
\begin{array}{l} 2 f=-12 \\ f=\square \end{array}
2
f
=
−
12
f
=
□
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Solve for
w
w
w
:
\newline
w
−
15
=
−
4
w
=
□
\begin{array}{l} w-15=-4 \\ w=\square \end{array}
w
−
15
=
−
4
w
=
□
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Evaluate
−
2
5
−
x
+
(
−
9
10
)
-\frac{2}{5}-x+\left(-\frac{9}{10}\right)
−
5
2
−
x
+
(
−
10
9
)
where
x
=
4
5
x=\frac{4}{5}
x
=
5
4
.
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Solve for
n
n
n
.
\newline
n
8
=
11
5
n
=
\begin{array}{l} \frac{n}{8}=\frac{11}{5} \\ n= \end{array}
8
n
=
5
11
n
=
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Solve for
r
r
r
.
\newline
4
r
=
5
7
r
=
□
\begin{array}{l} \frac{4}{r}=\frac{5}{7} \\ r=\square \end{array}
r
4
=
7
5
r
=
□
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Solve for
r
r
r
.
\newline
r
5
=
4
7
r
=
□
\begin{array}{l} \frac{r}{5}=\frac{4}{7} \\ r=\square \end{array}
5
r
=
7
4
r
=
□
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Which value of
h
h
h
makes
8
+
h
10
=
1
\frac{8+h}{10}=1
10
8
+
h
=
1
a true statement?
\newline
Choose
1
1
1
answer:
\newline
(A)
h
=
1
h=1
h
=
1
\newline
(B)
h
=
2
h=2
h
=
2
\newline
(C)
h
=
3
h=3
h
=
3
\newline
(D)
h
=
4
h=4
h
=
4
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Which value of
w
w
w
makes
14
=
11
+
w
8
⋅
6
14=11+\frac{w}{8} \cdot 6
14
=
11
+
8
w
⋅
6
a true statement?
\newline
Choose
1
1
1
answer:
\newline
(A)
w
=
1
w=1
w
=
1
\newline
(B)
w
=
4
w=4
w
=
4
\newline
(C)
w
=
16
w=16
w
=
16
\newline
(D)
w
=
24
w=24
w
=
24
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Find
lim
x
→
5
x
+
2
x
2
−
5
\lim _{x \rightarrow 5} \frac{x+2}{x^{2}-5}
lim
x
→
5
x
2
−
5
x
+
2
.
\newline
Choose
1
1
1
answer:
\newline
(A)
−
3
25
-\frac{3}{25}
−
25
3
\newline
(B)
7
20
\frac{7}{20}
20
7
\newline
(C)
−
7
25
-\frac{7}{25}
−
25
7
\newline
(D) The limit doesn't exist
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