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Math Problems
Algebra 2
Symmetry and periodicity of trigonometric functions
Max tried to find
lim
x
→
π
2
sin
(
2
x
)
cos
(
x
)
\lim _{x \rightarrow \frac{\pi}{2}} \frac{\sin (2 x)}{\cos (x)}
lim
x
→
2
π
c
o
s
(
x
)
s
i
n
(
2
x
)
.
\newline
Using direct substitution, he got
0
0
\frac{0}{0}
0
0
.
\newline
For Max's next step, which method would apply?
\newline
Choose
1
1
1
answer:
\newline
(A) Factorization and cancellation
\newline
(B) Rationalization using conjugates
\newline
(C) Alternate forms of trigonometric functions
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Function
f
f
f
is graphed.
\newline
According to the graph, is
f
f
f
even, odd, or neither?
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
Get tutor help
Is the following function even, odd, or neither?
\newline
f
(
x
)
=
4
x
+
2
f(x)=4 x+2
f
(
x
)
=
4
x
+
2
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
Get tutor help
Is the following function even, odd, or neither?
\newline
f
(
x
)
=
x
4
+
x
f(x)=x^{4}+x
f
(
x
)
=
x
4
+
x
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
Get tutor help
Is the following function even, odd, or neither?
\newline
f
(
x
)
=
5
x
f(x)=5 x
f
(
x
)
=
5
x
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
Get tutor help
Is the following function even, odd, or neither?
\newline
f
(
x
)
=
2
x
+
3
f(x)=2^{x+3}
f
(
x
)
=
2
x
+
3
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
Get tutor help
Is the following function even, odd, or neither?
\newline
f
(
x
)
=
x
3
−
x
f(x)=\sqrt[3]{x}-x
f
(
x
)
=
3
x
−
x
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
Get tutor help
Is the following function even, odd, or neither?
\newline
f
(
x
)
=
x
3
x
+
1
f(x)=\frac{x^{3}}{x+1}
f
(
x
)
=
x
+
1
x
3
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
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Is the sine function even or odd?
\newline
Choices:
\newline
[A]even
\text{[A]even}
[A]even
\newline
[B]odd
\text{[B]odd}
[B]odd
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