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Math Problems
Algebra 2
Evaluate natural logarithms
If
f
(
x
)
=
−
3
−
20
+
x
f(x)=\frac{-3}{-20+\sqrt{x}}
f
(
x
)
=
−
20
+
x
−
3
, what is the value of
f
(
3
)
f(3)
f
(
3
)
, to the nearest tenth (if necessary)?
\newline
Answer:
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Apply the distributive property to factor out the greatest common factor.
\newline
8
x
−
20
=
8 x-20=
8
x
−
20
=
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Apply the distributive property to factor out the greatest common factor.
\newline
16
g
+
20
h
=
16 g+20 h=
16
g
+
20
h
=
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Apply the distributive property to factor out the greatest common factor.
\newline
20
+
4
k
=
20+4 k=
20
+
4
k
=
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Apply the distributive property to factor out the greatest common factor.
\newline
14
k
+
35
=
14 k+35=
14
k
+
35
=
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Apply the distributive property to factor out the greatest common factor of all three terms.
\newline
10
a
−
25
+
5
b
=
10 a-25+5 b=
10
a
−
25
+
5
b
=
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Apply the distributive property to factor out the greatest common factor.
\newline
4
+
10
=
4+10=
4
+
10
=
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Apply the distributive property to factor out the greatest common factor.
\newline
12
+
80
=
12+80=
12
+
80
=
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Combine the like terms to create an equivalent expression.
\newline
9
+
a
−
5
b
−
2
9+a-5b-2
9
+
a
−
5
b
−
2
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Combine the like terms to create an equivalent expression.
\newline
7
+
4
c
+
2
d
+
3
7+4c+2d+3
7
+
4
c
+
2
d
+
3
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Combine the like terms to create an equivalent expression.
\newline
m
+
8
+
6
n
−
3
=
m+8+6n-3=
m
+
8
+
6
n
−
3
=
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Combine the like terms to create an equivalent expression.
\newline
5
z
−
3
+
3
z
=
5z-3+3z=
5
z
−
3
+
3
z
=
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Combine the like terms to create an equivalent expression.
\newline
2
q
+
2
+
9
2q+2+9
2
q
+
2
+
9
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Combine the like terms to create an equivalent expression.
\newline
7
k
+
3
k
+
11
=
7k+3k+11=
7
k
+
3
k
+
11
=
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Combine the like terms to create an equivalent expression.
\newline
5
+
9
t
+
3
=
5+9t+3=
5
+
9
t
+
3
=
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Combine the like terms to create an equivalent expression.
\newline
4
n
+
11
+
2
n
=
4n+11+2n=
4
n
+
11
+
2
n
=
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Evaluate. Write your answer as a whole number, proper fraction, or improper fraction in simplest form.
\newline
ln
(
e
)
10
=
\frac{\ln (e)}{10} =
10
l
n
(
e
)
=
______
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